Suppose you want to make a muon
antimuon pair (μ) by
colliding and annihilating a positron and an electron.
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(1) |
The (muon) μ particles
are each about 200 times the mass of an electron, so most of the kinetic
energy of the electron and positron must be used to create them.
The positron e+ could be fired at a stationary electron (in
practice the electron would be bound in an atom with kinetic energy of a
few eV, which is negligible compared with the high energies
involved in Particle Physics).
The incident positron (e+) has momentum pe
and total energy Ee and collides with a
stationary electron (e-) thereby annihilating to produce a
'virtual photon'. The virtual photon materialises into a new e+
and e- pair or any other heavier particle antiparticle pair,
such as μ+
and μ-,
provided sufficient energy is available. The μ+
and μ-
pair must have total momentum equal to pe in order to
conserve momentum in the collision.
Combining the relativistic energy and the momentum conservation equations
yields the equation below:
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(2) |
Derivation of this result
This is the positron total energy at which particles are
produced with the least possible momentum, it is therefore the threshold
energy.
Put the masses into this equation and calculate (use Excel etc. or a calculator) the threshold total
energy for pair production by positrons hitting a stationary target:
Particle |
Mass in MeV/c2 |
"Colour" |
electron |
0.511 |
blue / red |
muon |
105.7 |
green /dark green |
pion |
139.6 |
magenta |
kaon |
493.7 |
yellow |
proton |
938.3 |
grey / dark grey |
Explanation of Particle Physics units
The actual type of particle antiparticle pair created is random once you are above the threshold energy. Thus you might simply create a new electron positron pair even though you have enough energy to make muons. You need to repeat the experiment a few times before increasing the beam energy.
Now run the
animation and test your prediction for the threshold energy.
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